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Movement for 5 tables

edited 8:50AM in EBU TDs
In our club, some players favour a 5-Table Howell whilst others Mitchell. Which one is more fairer mathematically? Grateful for your comments.

Comments

  • A full Howell is fairest because every pair plays every other pair. However with 10 pairs that means 9 rounds and likely to be 27 boards. Our club finds that too many. If you curtail the Howell it is less fair. You can play a 3/4 Howell but then not all pairs play each other, or a Hesitation Mitchell (6 rounds) which is similar. Maybe a Mitchell is fairer than an incomplete Howell especially if you only compare the two ranks separately as all pairs in each rank play all other pairs in the other rank, provided you complete all rounds which with 5 tables you will. However you be playing 5 board rounds, probably, which to my mind is less fun than 3 board rounds and more variety of opposition (I know that is not the question you asked). I prefer the Hesitation Mitchell as it is an easy movement for the players and a good compromise.

  • I don't think Tim's response could be bettered.

  • Yes Tim thank you so much for you much detailed response.
  • Surprisingly, according to the Manning equality-of-competition algorithm, where 0 is perfectly balanced, the 5 table 3/4 Howell, eg [M38], is better balanced than the full Howell, eg [ M39], having a factor of 1.59 vs 1.81. The Hesitation Mitchell [M47-5] has a factor of 2.10.

    Tim's explanation above should say ... Mitchell is fairer ... only if you compare the two ranks separately... (ie leave out "especially"). Each side has a factor of 0 but the sides are not comparable.

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